kernel: backport ARM memset fixes for GCC 4.7/4.8
[openwrt/svn-archive/archive.git] / target / linux / generic / patches-3.3 / 002-ARM-7668-1-fix-memset-related-crashes-caused-by-rece.patch
1 From 418df63adac56841ef6b0f1fcf435bc64d4ed177 Mon Sep 17 00:00:00 2001
2 From: Nicolas Pitre <nicolas.pitre@linaro.org>
3 Date: Tue, 12 Mar 2013 13:00:42 +0100
4 Subject: [PATCH] ARM: 7670/1: fix the memset fix
5
6 Commit 455bd4c430b0 ("ARM: 7668/1: fix memset-related crashes caused by
7 recent GCC (4.7.2) optimizations") attempted to fix a compliance issue
8 with the memset return value. However the memset itself became broken
9 by that patch for misaligned pointers.
10
11 This fixes the above by branching over the entry code from the
12 misaligned fixup code to avoid reloading the original pointer.
13
14 Also, because the function entry alignment is wrong in the Thumb mode
15 compilation, that fixup code is moved to the end.
16
17 While at it, the entry instructions are slightly reworked to help dual
18 issue pipelines.
19
20 Signed-off-by: Nicolas Pitre <nico@linaro.org>
21 Tested-by: Alexander Holler <holler@ahsoftware.de>
22 Signed-off-by: Russell King <rmk+kernel@arm.linux.org.uk>
23 ---
24 arch/arm/lib/memset.S | 33 +++++++++++++--------------------
25 1 file changed, 13 insertions(+), 20 deletions(-)
26
27 diff --git a/arch/arm/lib/memset.S b/arch/arm/lib/memset.S
28 index d912e7397ecc..94b0650ea98f 100644
29 --- a/arch/arm/lib/memset.S
30 +++ b/arch/arm/lib/memset.S
31 @@ -14,31 +14,15 @@
32
33 .text
34 .align 5
35 - .word 0
36 -
37 -1: subs r2, r2, #4 @ 1 do we have enough
38 - blt 5f @ 1 bytes to align with?
39 - cmp r3, #2 @ 1
40 - strltb r1, [ip], #1 @ 1
41 - strleb r1, [ip], #1 @ 1
42 - strb r1, [ip], #1 @ 1
43 - add r2, r2, r3 @ 1 (r2 = r2 - (4 - r3))
44 -/*
45 - * The pointer is now aligned and the length is adjusted. Try doing the
46 - * memset again.
47 - */
48
49 ENTRY(memset)
50 -/*
51 - * Preserve the contents of r0 for the return value.
52 - */
53 - mov ip, r0
54 - ands r3, ip, #3 @ 1 unaligned?
55 - bne 1b @ 1
56 + ands r3, r0, #3 @ 1 unaligned?
57 + mov ip, r0 @ preserve r0 as return value
58 + bne 6f @ 1
59 /*
60 * we know that the pointer in ip is aligned to a word boundary.
61 */
62 - orr r1, r1, r1, lsl #8
63 +1: orr r1, r1, r1, lsl #8
64 orr r1, r1, r1, lsl #16
65 mov r3, r1
66 cmp r2, #16
67 @@ -127,4 +111,13 @@ ENTRY(memset)
68 tst r2, #1
69 strneb r1, [ip], #1
70 mov pc, lr
71 +
72 +6: subs r2, r2, #4 @ 1 do we have enough
73 + blt 5b @ 1 bytes to align with?
74 + cmp r3, #2 @ 1
75 + strltb r1, [ip], #1 @ 1
76 + strleb r1, [ip], #1 @ 1
77 + strb r1, [ip], #1 @ 1
78 + add r2, r2, r3 @ 1 (r2 = r2 - (4 - r3))
79 + b 1b
80 ENDPROC(memset)
81 --
82 1.8.3.2
83